>>> b = lambda x: lambda: x  # Lambdas can return other lambdas!
>>> c = b(88)
>>> c
>>> c()

>>> higher_order_lambda = lambda f: lambda x: f(x)
>>> g = lambda x: x * x
>>> higer_order_lambda(2)(g)
>>> higer_order_lambda(g)(2)

In [10]: p=print('1')
1

In [11]: p

s_list=split(remove_punctuation(lower(s)))

(function) def split(s: Any) -> Any
Return a list of words contained in s, which are sequences of characters separated by whitespace (spaces, tabs, etc.).

>>> split("It's a lovely day, don't you think?")
["It's", 'a', 'lovely', 'day,', "don't", 'you', 'think?']

(function) def remove_punctuation(s: Any) -> Any
Return a string with the same contents as s, but with punctuation removed.

>>> remove_punctuation("It's a lovely day, don't you think?")
'Its a lovely day dont you think'
    >>> remove_punctuation("Its a lovely day dont you think")
'Its a lovely day dont you think'

def counts(curr_start,curr_goal,cnt):
        if cnt > limit:
            return limit + 1
        
        if not curr_start and not curr_goal:
            return cnt
        elif not curr_start or not curr_goal:
            return counts(curr_start[1:], curr_goal[1:], cnt + 1)
        elif curr_start[0] == curr_goal[0]:
            return counts(curr_start[1:], curr_goal[1:], cnt)
        else:
            return counts(curr_start[1:], curr_goal[1:], cnt + 1)

    return counts(typed,reference,0)
    #在Python中，curr[1:]这个表达式是在进行切片操作。这个表达式表示从curr这个序列（这个序列可能是列表、元组或字符串等）中，取出下标为1的元素到最后一个元素组成的子序列。Python的切片操作非常强大，基本形式是[start:end]，其中start是起始下标，end是结束下标，切片的结果包含start对应的元素，但不包含end对应的元素。